how many naoh should required to make 50 ml of 0.5 mol / l of solutions of naoh ?
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Answer:
The amount of NaOH required is 1g
Explanation:
Molarity of NaOH = 0.5mol/litre
Volume = 50ml = 0.05Litre
Molarity = no of moles ÷ Volume(in Litre)
0.05 = no of moles ÷ 0.05
Implies number of moles = 0.5 × .05 = 0.025
Molecular Weight of NaOH = 40g
Weight of substance required = molecular weight × no of moles
Implies Amount of NaOH required = 40×0.025 = 1g
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