how many natural number between 300 and 500 divisble by 7
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301,308,315.........448
an=a+(n-1)d
an=301+(n-1)7
448-301=7n-7
147+7=7n
154/7=n
22=n
an=a+(n-1)d
an=301+(n-1)7
448-301=7n-7
147+7=7n
154/7=n
22=n
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