how many natural numbers are there between 123 and 999 that are completely divisible by 7?
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Hi,
Here is your answer
Natural numbers which are divisible by 7 in between 123 and 999 are = 126, 133......994.
These are in the form of an arithmetic progression with first term 126 and common difference 7 and the last term is 994.
Last term = first term + (number of terms - 1) common difference
994 = 126 + (n - 1)7
994 = 126 + 7n - 7
994 - 119 = 7n
7n = 875
n = 125
The number of terms in between 123 and 999 which are divisible by 7 = 125
Hope this helps you.
Here is your answer
Natural numbers which are divisible by 7 in between 123 and 999 are = 126, 133......994.
These are in the form of an arithmetic progression with first term 126 and common difference 7 and the last term is 994.
Last term = first term + (number of terms - 1) common difference
994 = 126 + (n - 1)7
994 = 126 + 7n - 7
994 - 119 = 7n
7n = 875
n = 125
The number of terms in between 123 and 999 which are divisible by 7 = 125
Hope this helps you.
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