Question

how many natural numbers are there between 200 and 500 which are divisible by 7

Answer 1

HEY MATE....

HERE IS YOUR ANSWER

First no. divisible by 7 b/w 200 and 500 = 203

Last no. divisible by 7 b/w 200 and 500 = 497

Difference between two consecutive terms (d) = 7

an = a + (n - 1)d

⇒ 497 = 203 + (n-1)7

⇒ 497 - 203 = 7n - 7

⇒ 294 + 7 = 7n

⇒ 301/7 =n

43 = n

43 numbers are divisible by 7 b/w 200-500.

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Answer 2

Answer:

Step-by-step explanation:

First number divisible by 7 is 203

Last number is divisible by 7 is 497

D is 7

So,

an = a + (n - 1)d

⇒ 497 = 203 + (n-1)7

⇒ 497 - 203 = 7n - 7

⇒ 294 + 7 = 7n

⇒ 301/7 =n

43 = n

43 numbers are divisible by 7 between 200-500.

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