how many natural numbers between 300 and 700gives remainder 1divided by 6?
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66;
by using arthrmetic progression
first number divided by 6=306
last number divided by 6=696
then by using formula
696=306+(n-1)6
696-306=(n-1)6
390=(n-1)6
n-1=390/6
n-1=65
n=66
by using arthrmetic progression
first number divided by 6=306
last number divided by 6=696
then by using formula
696=306+(n-1)6
696-306=(n-1)6
390=(n-1)6
n-1=390/6
n-1=65
n=66
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