How many natural numbers divisible by 7 are there between 3 and 200?
Answers
Answered by
29
Hey sup!
a=7 (First number divisible by 7 in the range)
d=7(As the number is to be divisible by 7).
l=196(last number divisible by 7in the range).
=>T(n)=a+(n-1)d.
=>196=7+(n-1)7.
=>196-7=(n-1)7.
=>189=(n-1)7.
=>189/7=n-1.
=>27=n-1.
=>n=27+1.
=>n=28.
There are 28 natural numbers divisible by 7 between 3 and 200.
Hope it helps.
a=7 (First number divisible by 7 in the range)
d=7(As the number is to be divisible by 7).
l=196(last number divisible by 7in the range).
=>T(n)=a+(n-1)d.
=>196=7+(n-1)7.
=>196-7=(n-1)7.
=>189=(n-1)7.
=>189/7=n-1.
=>27=n-1.
=>n=27+1.
=>n=28.
There are 28 natural numbers divisible by 7 between 3 and 200.
Hope it helps.
Answered by
19
a = 7
an = 196
d =7
n= ?
-------------------------------
an = a + (n-1)d
196 = 7 + (n-1)7
189 = (n-1)7
27 = n-1
n = 28
28 natural numbers are divisible by 7 between 3 and 200
an = 196
d =7
n= ?
-------------------------------
an = a + (n-1)d
196 = 7 + (n-1)7
189 = (n-1)7
27 = n-1
n = 28
28 natural numbers are divisible by 7 between 3 and 200
Denil:
I do not understand your answer
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