Question

How many natural numbers lie between 1000 power2 and 1001 power 2

Answer 1

1000×1000=1000000- 1001 =998999

Answer 2

HERE'S YOUR ANSWER
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(1001)^2 = (1000+1)^2 = 1000^2 + 1 + 2×1000×1 = 1000000 + 1 + 2000 = 1002001 ___(a)

(1000)^2 = 1000×1000 = 1000000 ___(b)

Subtracting (b) from (a), we get

(1001)^2 - (1000)^2 = 1002001 - 1000000 = 2001

Therefore, the required number of natural numbers that lie between (1000)^2 and (1001)^2 are 2001.
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