Question

How many natural numbers lie between n2 and (n + 1)2 ?
(A) 2n
(B) 2n-1
(C) 2n + 1
(D) n2​

Answer 1

Answer:

As there are 2n natural numbers which lie between two consecutive perfect square numbers

n

2

and

(

n

+

1

)

2

. Therefore, between

111

2

and

112

2

, there are

2

×

111

=

222

natural numbers.