How many natural numbers lie between
![{11}^{2} {11}^{2}](https://tex.z-dn.net/?f=+%7B11%7D%5E%7B2%7D+)
and
![{12}^{2} {12}^{2}](https://tex.z-dn.net/?f=+%7B12%7D%5E%7B2%7D+)
?
A. 22
B. 23
C. 24
D. 25
Answers
Answered by
3
Answer:
11^2 = 121
12^2 =144
so 144-121= answer
which is 23
so B.23
Step-by-step explanation:
hope it helps you mark brainliest
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