Math, asked by swarupmanna2003, 9 months ago


How many natural numbers lie between the squares of the following numbers
(a) 12 and 13 (b) 19 and 20 (c) 25 and 26.​

Answers

Answered by haldaniharsh
1

Answer:

so, 50 numbers lie b/w the squares of 25 and 26

Answered by Anonymous
14

Answer:

to find no. of natural number between squares of n and n+1, we would find 2n

Step-by-step explanation:

a) n = 12

n+1 = 13

2n = 24

b) n = 19

n+1 = 20

2n = 38

c) n = 25

n+1 = 26

2n = 50

therefore there are 24 , 38 and 50 natural nos. respectively in the squares of above answers

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