Question

how many natural numbers lies between 8^2 and 9^2​

Answer 1

Answer:

18, Natural No.

Step-by-step explanation:

1) 8² = 64

2) 9² = 81

3) 81 - 64 + 1 = 18

Answer 2

Answer:

There are $16$ natural numbers that lies between $8^2$ and $9^2$.

Step-by-step explanation:

Concept:

Any integer greater than zero that is a natural number. Natural numbers, such as $1, 2, 3, 4, 5....$, start at $1$ and go on forever. Because they are employed for counting, natural numbers are often known as "counting numbers."

Given:

$8^2$ and $9^2$

To find:

We have to find the count of natural numbers that lies between $8^2$ and $9^2$.

Solution:

There are total $16$ natural numbers between $8^2$ and $9^2$.

We are aware that there are $2n$ natural numbers, where $n$ is a lower integer, between any two perfect squares.

Thus,

Here $n= 8,$

so,

$2n = 2*8\\=16$.

Hence, there are $16$ natural numbers that lies between $8^2$ and $9^2$.

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