How many natural numbers of four digits can be formed if the digits are 2,3,5,0 repetitions are not allowed
Answers
Answer:
Clearly, with digits 5, 4, 3 and 2; we can form (4*4*4*4) = 256 four-digit numbers - out of which [1*1*4*4] = 16 are larger than 5432. (Only those are larger than 5432; who have 5 at thousand’s and hundred’s places both).
So, total number of four-digit numbers not exceeding 5432 = (256 - 16) = 240.
Now, three-digit, two-digit and single digit numbers all are smaller than 5432.
Number of three-digit numbers can be formed with digits 5, 4, 3 and 2 = (4*4*4) = 64.
Number of two-digit numbers can be formed with digits 5, 4, 3 and 2 = (4*4) = 16.
Number of single-digit numbers can be formed with digits 5, 4, 3 and 2 = 4.
Therefore, with digits 5, 4, 3 and 2; we can form (240 + 64 + 16 + 4) = 324 natural numbers.
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Answer:
The number of 4 digit natural numbers that can be formed is 18.
Step-by-step explanation:
This is a problem of Permutations and Combinations.
Given digits are 2, 3, 5, 0.
In order to create a 4 - digit number,
- Repetition of digits is not allowed.
- All the given digits should be used at a time.
- The number 0 should not appear in the first position or in thousands position.
Using the above rules, calculate the number of 4 - digit natural numbers possible. The possible ways are given below:
- The thousands position can be filled in 3 ways by (2,3,5). Then,
- The hundreds position can be filled in following way:
1000's - 2, 100's - 3, 5, 0, ways - 1*3 = 3
1000's - 3, 100's - 2, 5, 0, ways - 1*3 = 3
1000's - 5, 100's - 2, 3, 0, ways - 1*3 = 3
- The 100s position can be filled by 3 numbers in 9 possible ways
- Similarly, the 10s position can be filled with 2 numbers in
3*2 + 3*2 + 3*2 = 18
- The units place can be filled in 1 way.
Therefore the number of 4 digit natural numbers that can be formed
= 3 * 3 * 2 * 1 = 18
Therefore the number of 4 digit natural numbers that can be formed is 18.
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