How many nerve endings are there in our eyes??
Answers
The nerve endings of the approximately 1 million ganglion cells must leave the retina in one place and lead as an optic nerve into the brain.
Answer:
I hope it is helpful to you
Explanation:
particle start motion from rest according to formula θ=(t4/60)- (t/4). Then the angular velocity and angular acceleration at time t=10s.particle start motion from rest according to formula θ=(t4/60)- (t/4). Then the angular velocity and angular acceleration at time t=10s.particle start motion from rest according to formula θ=(t4/60)- (t/4). Then the angular velocity and angular acceleration at time t=10s.particle start motion from rest according to formula θ=(t4/60)- (t/4). Then the angular velocity and angular acceleration at time t=10s.particle start motion from rest according to formula θ=(t4/60)- (t/4). Then the angular velocity and angular acceleration at time t=10s.particle start motion from rest according to formula θ=(t4/60)- (t/4). Then the angular velocity and angular acceleration at time t=10s.particle start motion from rest according to formula θ=(t4/60)- (t/4). Then the angular velocity and angular acceleration at time t=10s.particle start motion from rest according to formula θ=(t4/60)- (t/4). Then the angular velocity and angular acceleration at time t=10s.particle start motion from rest according to formula θ=(t4/60)- (t/4). Then the angular velocity and angular acceleration at time t=10s.particle start motion from rest according to formula θ=(t4/60)- (t/4). Then the angular velocity and angular acceleration at time t=10s.particle start motion from rest according to formula θ=(t4/60)- (t/4). Then the angular velocity and angular acceleration at time t=10s.particle start motion from rest according to formula θ=(t4/60)- (t/4). Then the angular velocity and angular acceleration at time t=10s.particle start motion from rest according to formula θ=(t4/60)- (t/4). Then the angular velocity and angular acceleration at time t=10s.