Chemistry, asked by bujjijoshna62, 7 months ago

How many neutrons and electrons are present in the nuclei of 6^c^13, O^8^16, 12^mg^14,26^fe^56,38^sr^88?​

Answers

Answered by yashika8832
1

Answer:

For ¹³C6 neutrons =7 electrons=6

¹⁶O8 neutrons=8 electrons =8

here instead of ¹⁴Mg 12 ²⁴Mg12 should be there neutrons=12 electrons=12

⁵⁶Fe26 neutrons=30 electrons=26

⁸⁸Sr38 neutrons= 50 electrons=38

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