How many neutrons and electrons are present in the nuclei of 6^c^13, O^8^16, 12^mg^14,26^fe^56,38^sr^88?
Answers
Answered by
1
Answer:
For ¹³C6 neutrons =7 electrons=6
¹⁶O8 neutrons=8 electrons =8
here instead of ¹⁴Mg 12 ²⁴Mg12 should be there neutrons=12 electrons=12
⁵⁶Fe26 neutrons=30 electrons=26
⁸⁸Sr38 neutrons= 50 electrons=38
Similar questions