Question

how many neutrons and proton are there in -
(i)8O16
(ii)26Fe56​

Answer 1

No. of protons = Mass number- No. of neutrons

No. of neutrons = Mass no. - No. of protons

No. of protons = Atomic number

No. of neutrons in  $O^1^6_8$ = 16 - 8 = 8

No. of protons = 16 - 8 = 8

No. of neutrons in $Fe^5_2^6_6$ = 56 - 26 = 30

No. of protons = 56 - 30 = 26

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