Question

How many nitrogen atoms are present in 12 grams of sodium azide?

Answer 1

Answer:

There are infinite nitrogen atoms are present in 12 grams of sodium azde

Explanation:

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Answer 2

Explanation:
We're asked to find the mass, in
g
, of sodium azide (
NaN
3
) needed to produce a certain amount of
N
2
.
To do this, we can use the ideal gas equation to find the moles of nitrogen gas present:
P
V
=
n
R
T
P
=
1.15

atm
(given)

V
must be in liters, so we can find the volume first in
cm
3
and then convert:

50.0
×
50.0
×
25.0
=
62500

cm
3
62500
cm
3
(
1
mL
1
cm
3
)
(
1
l
L
10
3
mL
)
=
62.5

L
R
is the universal gas constant, equal to
0.082057
L
⋅
atm
mol
⋅
K

T
=
25.0

o
C
, which must be in Kelvin:

T
=
25.0

o
C
+
273
=
298

K
Plugging in known values, and solving for the number of moles,
n
, we have
n
=
P
V
R
T
=
(
1.15
atm
)
(
62.5
L
)
(
0.082057
L
⋅
atm
mol
⋅
K
)
(
298
K
)
=
2.94

mol N
2
Now, we can use the coefficients of the chemical equation to find the relative number of moles of sodium azide that must react:
2.94
mol N
2
(
2
l
mol NaN
3
3
mol N
2
)
=
1.96

mol NaN
3
Finally, we can use the molar mass of sodium azide (
65.01

g/mol
) to find the mass in grams:
1.96
mol NaN
3
(
65.01
l
g NaN
3
1
mol NaN
3
)
=
127
l
g NaN
3
−−−−−−−−−−