how many no are there less than 1000 whose sum is divisible by 7 and no itself by 3
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there are 15 numbers
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The sum of numbers is divisible by 7 and the no itself is divisible by 3 which means that the sum of no.s is divisible by 21....
Now the largest 3 digit number is 999 whose sum of digits is 27 which means that the sum of digits of the no. can never be divisible by any other multiple of 21 other than 21...
Therefore we have to calculate no.s whose sum of digits is 21 which you can see the following manner....
9+9+3
9+8+4
9+7+5
......
.....
.....
..and you would get 28 possibilities
Hence the answer is 28
Hope this helps
And if it helped please mark as brainliest
Now the largest 3 digit number is 999 whose sum of digits is 27 which means that the sum of digits of the no. can never be divisible by any other multiple of 21 other than 21...
Therefore we have to calculate no.s whose sum of digits is 21 which you can see the following manner....
9+9+3
9+8+4
9+7+5
......
.....
.....
..and you would get 28 possibilities
Hence the answer is 28
Hope this helps
And if it helped please mark as brainliest
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