Question

how many no. lie between 10 and 600 which when divided by 3 gives remainder 2
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Answer 1

Answer:

Step-by-step explanation:

We know that the first number will be 11 (first 2 digit number giving remainder 2)

The next number will be 14 (the next number)

And the last number will be 599

So it will form an A.P. which is 11,14,17....599

a= 11

d= 3

l = 599 ( last number in the series giving the remainder 2)

l = a+(n-1)d

599 = 11 + (n-1)3

588 = (n-1)3

n-1 = 196

n = 197

So there are 197 numbers between 10 and 600 that leave remainder 2 after dividing by 3

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