Question

how many no. of atoms present in 28 gm of nitrogen?​

Answer 1

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Therefore no of atoms in 28 gms of nitrogen = 6 x 1 x 10 to the power -23. 1 mole of every matter contains 6.022 × 10²³ number of particles. No of atoms are 2×6.022×10^23 atoms.

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Answer 2

Answer:

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