how many no. of c-atoms present in 250 gram CaCo3?
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CaCO3
Molar weight → 40+12+48 = 100g
In 100g, C atoms → 12g i.e. 6.022×10^23
In 250g, 12/100 ×250 = 30g
i.e. 6.022×10^23 /12 ×30
=> 10.055 × 10^23
Molar weight → 40+12+48 = 100g
In 100g, C atoms → 12g i.e. 6.022×10^23
In 250g, 12/100 ×250 = 30g
i.e. 6.022×10^23 /12 ×30
=> 10.055 × 10^23
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