Question

how many no of molecules and atoms respectively are present in 2.8 liters of a diatomic gas at STP​

Answer 1

Explanation:

Volume of diatomic gas = 2.8 L

At STP,

22.4 L volume of gas contains 2\times 6.023\times 10^{23} atoms

2.8 L volume of gas contains 2\times 6.023\times 10^{23}\times \frac{2.8L}{22.4L}=15.056\times 10^{22} atoms

Therefore, the number of atoms present in 2.8 L is, 15.056\times 10^{22}