Chemistry, asked by sbfaraaz2591, 9 months ago

How many no. of moles in 52u of helium?

Answers

Answered by Brâiñlynêha
4

\huge\mathbb{SOLUTION:-}

\boxed{\sf{\purple{1\:mole\:of\:He=6.022\times 10{}^{23}}}}

\tt\:A.M.U\:of\: Helium (He)= 4unit\\ \\ \sf\longrightarrow So\:,\:1\:mole\:of\:He=4u\\ \\ \sf\longrightarrow 52u=\cancel{\dfrac{52}{4}}\\ \\ \sf\implies 52u=13moles

Now the calculate the number of moles

\sf\implies 1\:mole=6.022\times 10{}^{23}atoms\\ \\ \sf\implies 13\:moles=13\times 6.022\times 10{}^{23}atom\\ \\ \sf\implies 13\:moles=78.286\times 10{}^{23}atom\\ \\ \sf\implies \:\:or\:\: 7.8286\times 10{}^{24}atom

\boxed{\sf{\purple{No.\:of\:moles\:in\:52u\:He= 13\:moles}}}

\underline{\dag{\sf{\purple{No..\:of\:atom\:=7.8286\times 10{}^{24}atoms}}}}

Answered by Anonymous
54

we know that ,

1 mole of helium = 6.022×10²³

Atomic mass of helium =4u

=>1 mole of helium =4u

=>52u =52/4

 \mathbf \red{=>52u=13}

Now,

1 mole =6.022×10²³

=>13 moles=13×6.022×10²³

=>13 moles = 78.286×10²³

  \star \mathbf \red{no. \: of \: moles \: in \: 52u \: of \: he = 78.286 \times 10 {}^{23} }

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