Question

how many no.s of 2 digits are divisible by 7?
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Answer 1

Answer:

The two digits number starts from 10 and last term is 99 for this we use AP

So the first two number digit which is divisible by 7 is 14

Therefore a0= 14

A1=21

A2=28

Series is given by

14,21,28….

So d=a2-a1=28–21=7

To find last two digit 99÷7 then we get quotient 14 and reminder 1

Now multiply 14 with 7. we get 98 so last two digit number divisible by 7

So an=98

& d=7

So therefore by the formula we have

An=ao+(n-1)d

98=14+(n-1)7

98–14=(n-1)7

84=(n-1)7

84/7=n-1

12=n-1

n=12+1=13

so n=13 is the required answer. There are 13 two digit nu

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