How many NO2required for producing 4gram moles of HNO3
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Answer:
1.025 x 10^23
Explanation:
2NO2 + H2O ------------ HNO3 + HNO2
Moles of NO2 = N/6.022 x 10^23
Moles of HNO3 = 4/47
N/6.022 x 10^23 X 47/4 = 2/1
N = 6.022 x 10^23 x 4 x 2 X 1/47
N = 1.025 x 10^23
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