Question

How many nombers from 1001 to 2000 are divisible by 4

Answer 1

$\huge{\underline{\overline{\mathfrak{\fcolorbox{black}{grey}{Solution:-}}}}}$

Answer:

250 numbers are divisible by 4 from 1001 to 2000.

Step-by-step explanation:

The numbers from 1001 to 2000 which are divisible by 4 are : 1004, 1008, 1012,.............,1992, 1996, 2000

So, we can see this forms an A.P with common difference(d) = 4 and to find numbers from 1001 to 2000 divisible by we can simply find the number of terms in the above formed A.P. :

First Term, a = 1004

Common difference, d = 4

Last term, l = 2000

and n is required no. of terms

Now, l = a + (n - 1)·d

⇒ 2000 = 1004 + (n - 1)·4

⇒ 996 = (n - 1)·4

⇒ n - 1 = 249

⇒ n = 250

Hence, 250 numbers are divisible by 4 from 1001 to 2000.

Answer 2

$\underline \mathbb{SOLUTION}$

》250 numbers are divisible by 4 from 1001 to 2000.

So, The numbers from 1001 to 2000 which are divisible by 4 are:

1004 , 1008 , 1012 , ...........1992 , 1996 , 2000

$\underline \mathbb{SO}$

Here,

d = 4

We have to find n.

FIRST TERM, a = 1004

l = 2000

N = ?

$l = a + (n - 1)d$

$= > 2000 = 1004 + (n - 1)4$

$= > 996 = (n - 1)4$

$= > n - 1 = 249$

$= > n = 250$

$\underline \mathbb{HENCE}$

»250 NUMBERS ARE DIVISIBLE BY 4 FROM 1001 TO 2000.

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