Question

How
many non-
square rectangles
are possible with
their sides as natural
numbers such that
the perimeter of
each
rectangle is
20? Consider that
the breadth of each
rectangle is always
greater than its
length.​

Answer 1

Answer:

14 answer 14.

Step-by-step explanation:

answer 14 .

Answer 2

Answer:

There are four possibilities.

Step-by-step explanation:

The perimeter refers to the boundary of the rectangle.

The perimeter if given as $20$.

We need to determine that how many non-square rectangles are possible with their sides as natural numbers such that the perimeter of each rectangle is $20$.

It means sum of length and breadth should be $10$.

The possible $(l,b)$ can be $(1,9)(2,8)(3,7)(4,6)$

We can not take $(5,5)$ as both cannot be same. If they will be same, it will be a square.

The possibilities are $4$.

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