how many nubers of
two digit are visible by 3
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First two digit number divisible by 3 = 12
Last two digit number divisible by 3 = 99
An arithmetic progression (A.P) is a progression in which the difference between two consecutive terms is constant.
A.P = 12,15,18,…,99
here
First term (a) = 12
Common difference (d) = 3
Let us consider there are n numbers then
an = 99
a + (n – 1)d = 99
12 + (n – 1)3 = 99
12 + 3n – 3 = 99
n = 29+1
n = 30
∴ Two digit numbers divisible by 3 = 30.
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