how many number are the are there between 101 and 999 which are divisible by 2 and 5
Answers
Answered by
6
a = 110 {first number to be divided by 2 and 5}
difference d =10
an=990 {last no to be divided by 2 and 5}
an = a + {n - 1}d
990 = 110 + 10n -10
880 + 10 = 10n
890 = 10n
n = 89
Answered by
0
From 2 499 but from 5 I don't know may this help uh....
Similar questions