How many number between 100 to 200 divisible by 8?
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Answered by
5
Hiii friend,
AP = 104 , 112 , 120 ,......200
Here,
First term (A) = 104
Common difference (D) = 8
Tn = 200
N = ?
We know that,
Tn = A+(N-1) × D
200 = 104 + (N-1) × 8
104+8N -8 = 200
104 + 8N = 200-8
104 + 8N = 192
8N = 192-104
8N = 88
N = 88/8
N = 11
Hence,
11 NUMBERS are divisible by 8 between 100 to 200.
HOPE IT WILL HELP YOU..... :-)
AP = 104 , 112 , 120 ,......200
Here,
First term (A) = 104
Common difference (D) = 8
Tn = 200
N = ?
We know that,
Tn = A+(N-1) × D
200 = 104 + (N-1) × 8
104+8N -8 = 200
104 + 8N = 200-8
104 + 8N = 192
8N = 192-104
8N = 88
N = 88/8
N = 11
Hence,
11 NUMBERS are divisible by 8 between 100 to 200.
HOPE IT WILL HELP YOU..... :-)
Answered by
5
104
112
120
128
136
144
152
160
168
176
184
192
200
HOPE THIS☝️ IMAGE & TEXT WILL HELP YOU DEAR.......
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