How many number
number greater than 9
but less than 1000 have each
digit exceeding the digit
to its left?
Answers
Answer:
I think so five
Step-by-step explanation:
I hope so it will be uelpfull
Given : number greater than 9 but less than 1000
To Find : How many number have each digit exceeding the digit
to its left?
Solution:
Two digit
12 - 19
23 - 29
34 - 39
78 - 79
89
1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 = 36
Three Digit
starting with 1
23 - 29
34 - 39
78 - 79
89
1 + 2 + 3 + 4 + 5 + 6 + 7 = 28
starting with 2
34 - 39
78 - 79
89
1 + 2 + 3 + 4 + 5 + 6 = 21
and so on
36 + 28 + 21 + 15 + 10 + 6 + 3 + 1
= 120
There are 120 number greater than 9 but less than 1000 have each
digit exceeding the digit to its left
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