How many number of 2 digit numbers in which the digit in 10's place is greater than one's place?
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Say one's digit - x
ten's digit - y
If
x= 1, y={2,3,4,5,6,7,8,9}
x= 2, y={3,4,5,6,7,8,9}
:
:
x=8, y={9}
Number of Numbers = (8+7+....+1)
= 8(8+1)/2
= 9×4
= 36
36 such Numbers are possible
ten's digit - y
If
x= 1, y={2,3,4,5,6,7,8,9}
x= 2, y={3,4,5,6,7,8,9}
:
:
x=8, y={9}
Number of Numbers = (8+7+....+1)
= 8(8+1)/2
= 9×4
= 36
36 such Numbers are possible
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