How many number of atom present in 20gm of helium?
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Answer: 1 mole of He contains 6.023×10^23 atoms. 1 mole of He = 4 gm of He. So, 20 gm of He contains — (20÷4)×6.023×10^23 atoms = 3.011×10^24 He atoms
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Answer:
1 mole of the contains 6.023x10^23 atoms. 1 mole of He = 4gm of He so 20gm of He contains (20÷4)6.023x10^2 atoms =3.011x10^24 He atoms
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