Question

How many number of atoms present in 3.2 gram of sulphur?

Answer 1

..............................

Answer 2

Weight of 1 mol sulphur = molar mass of sulphur = 32 g

32 g = 1 mol

3.2 g = 0.1 mol

1 mol has 6.022*10^23 atoms

0.1 mol will have 6.022*10^22 atoms.