How Many Number Of Columns A Record Group Can Have?
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The simplest solution is to use a derived table:
Select Count(*)
From (
Select ...
From TempTable
Group By column_1, column_2, column_3, column_4
) As Z
Another solution is to use a Count Distinct:
Select ...
, ( Select Count( Distinct column_1,
column_2, column_3, column_4 )
From TempTable ) As CountOfItems
From TempTable
Group By column_1, column_2,
column_3, column_4
Hope this helps you ☺️☺️☺️
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