How many number of ions are there in 98 grams
of sulphate ions?
* 6.02 x 10
B. 6.02 x 10° 2
C. 4* 6.02 x 10 D. 3 x 6.02 x 10
ans with solution.
Answers
Answer:
A.some of the ethanol evaporated
B. the ethanol fills up the airspace between the water molecules
C. the liquids did not mix; ethanol floated on the surface of the water
D. all of the
A.some of the ethanol evaporated
B. the ethanol fills up the airspace between the water molecules
C. the liquids did not mix; ethanol floated on the surface of the water
D. all of the
A.some of the ethanol evaporated
B. the ethanol fills up the airspace between the water molecules
C. the liquids did not mix; ethanol floated on the surface of the water
D. all of the
A.some of the ethanol evaporated
B. the ethanol fills up the airspace between the water molecules
C. the liquids did not mix; ethanol floated on the surface of the water
D. all of the
A.some of the ethanol evaporated
B. the ethanol fills up the airspace between the water molecules
C. the liquids did not mix; ethanol floated on the surface of the water
D. all of the
A.some of the ethanol evaporated
B. the ethanol fills up the airspace between the water molecules
C. the liquids did not mix; ethanol floated on the surface of the water
D. all of the
A.some of the ethanol evaporated
B. the ethanol fills up the airspace between the water molecules
C. the liquids did not mix; ethanol floated on the surface of the water
D. all of the
A.some of the ethanol evaporated
B. the ethanol fills up the airspace between the water molecules
C. the liquids did not mix; ethanol floated on the surface of the water
D. all of the
A.some of the ethanol evaporated
B. the ethanol fills up the airspace between the water molecules
C. the liquids did not mix; ethanol floated on the surface of the water
D. all of the
A.some of the ethanol evaporated
B. the ethanol fills up the airspace between the water molecules
C. the liquids did not mix; ethanol floated on the surface of the water
D. all of the
Answer:
none of these
Explanation:
1SO4 ion =98g(molar mass)
so moles =given mass/molar mass=98/98=1mol
also, mol=number of ions/ Na
so number of ions=mol*Na=1×6.022×10^23