how many number of moles of glucose are present in 540grams of glucose
Answers
Answered by
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Molecular weight of glucose =180g
Thus, 180g =1 mole
So, 540 g= 540/180=3 moles.
Thus, 180g =1 mole
So, 540 g= 540/180=3 moles.
Answered by
1
Answer:
The number of moles of glucose are present in 540grams of glucose is 3 moles.
Explanation:
Given: Mass of glucose - 540gms
Find: number of moles of glucose
Step by step explanation :
formula used:
number of moles glucose = given mass of glucose/ molecular mass.
Molecular mass of glucose-180u
number of moles glucose =540gm/180=3moles
So ,the number of moles of glucose are present in 540grams of glucose is 3 moles.
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