Question

how many number of moles present in 10 gram of sugar(C12H32O11)​

Answer 1

Moles of C₁₂H₃₂O₁₁ is 0.028

Explanation:

First, we calculate the molecular weight of C₁₂H₃₂O₁₁

Molecular weight of C = 12 $gm / mole$

Total weight of C = 12 * 12 = 144

Molecular weight of H = 1 $gm / mole$

Total weight of H = 32 * 1 = 32

Molecular weight of O = 16 $gm / mole$

Total weight of O = 11 * 16 = 176

Adding for total molecular weight = 144 + 32 + 176

Total molecular weight of  C₁₂H₃₂O₁₁ = 352 $gm / mole$

Given:

Weight of C₁₂H₃₂O₁₁ = 10 grams

$Mole\ = \frac{weight}{Molecular\ weight}\\ Mole = \frac{10}{352}\\\\ Mole = 0.028$