How many number of two-digit positive integer than 100, which are not divisible and
5 is
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Answered by
3
Step-by-step explanation:
3 , 15 , 27, 39.....
First we need to calculate 54th term
We know that
aₙ = a + (n -1 )d
Here, a =3
d = 15 -3 =12
n = 54
Putting values in formula
a₅₄ = a + (n-1)d
= 3 + (54-1) ₓ12
=3 + 53 ₓ 12
= 3 + 636
= 639
So 54th term a₅₄
132 + 639
= 771
Therefore aₙ = 771
Putting value in formula
aₙ = a + (n-1)d
771 = 3 +(n-1) ₓ 12
771 -3 = (n-1) ₓ 12
768 /12 = n-1
64 = n-1
n = 65
65th term is 132 more than 54th term
Answered by
0
Answer:
Now integers are not divisible by 2 & 5 then, Integers ends with 0,2,4,5,6,8 will not include. Therefore 25 positive integers not greater than 100 are not divisible by 2,3 or 5.
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