Question

How many number of zero are their in Polynomial, P(x)=x^2-3 ?

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Answer 1

Answer:

Step-by-step explanation:

Given P(x)=x  3 −x

To find the zeros of P(x), let P(x)=0

⟹x  3  −x=0

⟹x(x  2  −1)=0

⟹x(x−1)(x+1)=0

⟹x=0 and x−1=0 and x+1=0

⟹x=0,1,−1 are the zeros of P(x)

Thus, the number of zeros of P(x) is 3.

Hence, the answer is 3.

Answer 2

Answer:

$\star \: \: p(x) = {x}^{2} - 3$

$\star \: \: {x}^{2} - 3 = 0$

$\star \: \: {x}^{2} = 3$

$\star \: \: x = ± \sqrt{3}$

$\star \: x = \sqrt{3} \: \: (or) \: \: x = - \sqrt{3}$

Since it is a quadratic equation, it has 2 zeroes