How many numbers arc there between 99 and 1000 such that the digit 8 occupies the units place?
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Answer:
i think the answer is 90
Step-by-step explanation:
the first 8 is in 108 and then in 118. so after every 10no.s there is a 8. and there 10 no.of 10s in one hundred and there 9 no.of hundreds so the total no. of 8s are = 10*9=90
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