How many numbers are divided by 9 between 101 and 999
Answers
For a natural number to be divisible by 2. its ending digit must be either 0, 2. 4. 6 and 8. For a natural number to be divisible by 5. its ending digit must be either 0 or 5. Therefore, a natural number, which is divisible by both 2 and 5, must have its ending digit equals to 0. Solution 1 Now, back to your question, a natural three-digit number between 101 and 999, which is divisible by both 2 and 5, must have its ending digit equals to 0. Let us write it as ab0. Now, replace a and b with any values of 0, 1, ... ,9 you will have the answer. For example: 110, 120, 130, .... 190, 200, 210, ... 290, ... , 970, 980 and 990. There are 89 numbers. Solution 2 As explained earlier, that number must have its ending digit equals to 0, meaning it is divisible by 10 (you can also conclude this right at beginning). So we have those numbers are: 110, 120, 130, ..., 970, 980 and 990. (by multiplying 10 with 11, 12, 13, ... 97, 98 and 99). There are 89 numbers.