Question

How many numbers are divided completly by 3 between 102 and 600?

Answer 1

Between 102 and 600
First number after 102 divisible by '3' is 105
Last number before 600 divisible by '3' is 597
To find the numbers.
105,108......597
An = A1 + (n-1)*d
597 = 105 + (n-1)*3
492 = (n-1)*3
164 = n-1
n = 165
So there are 165 numbers between 102 and 600 that are divisible by '3'

Answer 2

Hey!
Ur answer is ;-
This forma a A.P
first term of A.P is 102
last term of A.P is 600
nd c.d is 3
A.TQ
Tn = a+(n-1) d
600 = 102 +(n-1) 3
600 = 102 + 3n -3
600 = 99+3n
3n= 501
n = 501/3
n = 167

therefore, 167 mumbers are divisible by 3 btw 102 nd 600.

#riShu:-)