how many numbers are only divisible by 3 in 1 to 200
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first ,between 1 - 200
let we take the no. Divisible by 3 = x
And no. Divisible by 7 = y
And no. Divisible by both 3 & 7 = z
Between 1 to 200 multiples of 3 are
3,6 ,9...............198
So using Arithmetic progression last tern relation.
L = a + (n-1)d..................................(1)
L = 198
a=3
d=3
We get n = 66 =x
Similarly for 7 we get , y= 28.
Now the we will find the no.s which are divisible by both 3 and 7 for that we determine the no. divisible by 21 = 3×7
21,42,63..........189
Using relation 1 we get z = 9
Last step is
No. Divisible by 3 or 7 b/w 1 - 200 = (no.s divisible by 3 ) + (no.s divisible by 7) - (no.s divisible by both)
= X+Y-Z
= 66+28-9 = 85
Numbers divine by both 3 or 7 between 1 to 200 are 85.
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