Question

How
many numbers are possible between 666 and 8888​

Answer 1

Step-by-step explanation:

series would be 666,667,668………8886,8887,8888

this is in A.P

for last term is L= a+(n-1)d

where a is first term, here its 666 so , a = 666

d is common difference here common difference is 1

L= last term i.e 8888

n is no. of terms (to find)

Now, L= a+(n-1)d

we have, 8888 = 666+(n-1) *1

So, n = 8223

Total terms= 8223

Here it is asking for terms in between so excluding 1st and last term we have, 8223-2= 8221 terms.

Hope you got it.

Thank you.