How many numbers are there between 1 and 1000 which when divided by 7 leave remainder 4?
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first number = 4
last number = 998
9948 = 4 + (n-1)7
998 -4 = (n-1)7
994/7 = n-1
n = 142 - 1 = 141
numbers = 141
ckp22:
4 v to hota h
hmm?
ok thanks! corrected it
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