how many numbers are there between 100 and 1000 in which all the digits are distinct
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We know that numbers between 100 and 1000 will be 3 digit integers. Let the arrangement be ABC where A,B,C represent distinct digits. We have 9 options for A (as 0 can not start a 3 digit number), 9 options again for B and 8 for C, giving a total of 9*9*8 = 648 options. B is the correct answer.
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