Question

how many numbers are there between 200 and 500 which leave remainder 7 when divided by 9​

Answer 1

Answer:

n=33

Step-by-step explanation:

$t_{n}$ = a+(n-1)d

493 = 205 + (n-1) 9

493 - 205 = (n-1) 9

(n-1) 9 = 288

(n-1) = $\frac{288}{9}$

n-1 = 32

n = 32+1

n=33

Answer 2

Answer:

Here is your answer attached step by step explanation.

Step-by-step explanation:

Hope it will help.