How many numbers are there from 200 to 700 which are divisible by 2,3 and 5 ?
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Answer:
the answer should be 9
Step-by-step explanation:
Since the required numbers are divisible by 2, 3 and 7, let
common difference, d=2×3×7=42
To find out the first number of the series, divide 300 by 42. We get remainder=6. So, the first number of the series is given by
a=300+(42-6)
=336
Similarly, to find the last number of the series, divide 700 by 42. We get remainder=28. So, the last number of the series is given by
l=700-28
=672
Let n be the number of numbers divisible by 42 from 300 to 700
Therefore,
l=a+(n-1)d
672=336+(n-1)42
336/42=n-1
n=8+1
Therefore, n=9
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