How many numbers are there from 300 to 650 which are completely divisible by both 5 and 7
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hiii. .......friend
the answer is here,
If the number is divisible by both 5 & 7 .The it should be multiple of (5×7).
So, The multiples of 21 between 300 & 650 are,
=> 315,336,357,...............630.
These are in AP with common difference 21.
So, The no. of terms in the AP be n.
=> an =a+(n-1)d.
=> 630 =315 +(n-1)21.
=> 315 =(n-1)21.
=> n-1 =315/21
=> n-1 =15.
=> n=16.
So, There are 16 terms between 300 & 650 which are divisible by both 5 &7.
:-)Hope it helps u.
the answer is here,
If the number is divisible by both 5 & 7 .The it should be multiple of (5×7).
So, The multiples of 21 between 300 & 650 are,
=> 315,336,357,...............630.
These are in AP with common difference 21.
So, The no. of terms in the AP be n.
=> an =a+(n-1)d.
=> 630 =315 +(n-1)21.
=> 315 =(n-1)21.
=> n-1 =315/21
=> n-1 =15.
=> n=16.
So, There are 16 terms between 300 & 650 which are divisible by both 5 &7.
:-)Hope it helps u.
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