Math, asked by sanjeevkumarsanjay, 10 months ago

how many numbers are there in all , having :(a) 1-digit ------(b) 2digit----- (c) 3digit----​

Answers

Answered by adityabhargav1425
3

Answer:

Step-by-step explanation:

since 9 is the highest 1 digit positive number. therefore 9 numbers are there having positive sign. therefore 99 numbers are there having positive sign in 2 digits. therefore 999 numbers are there having positive sign in 3 igits.

Answered by halamadrid
0

Given; Numbers

To Find; how many numbers are there in all, having :(a) 1-digit ------(b) 2digit----- (c) 3digit----

Solution; One digit numbers are from one to nine.

Hence there are nine one-digit numbers

Two-digit numbers are from 10 to 99 is 90

Three-digit numbers are from 100 to 999 that is there are 900 numbers

Hence (a) 1-digit -9 (b) 2digit---90 (c) 3digit---900

Similar questions